(2x^2-3x-5)/(25-4x^2)

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Solution for (2x^2-3x-5)/(25-4x^2) equation:


D( x )

25-(4*x^2) = 0

25-(4*x^2) = 0

25-(4*x^2) = 0

25-4*x^2 = 0

-4*x^2 = -25 // : -4

x^2 = 25/4

x^2 = 25/4 // ^ 1/2

abs(x) = 5/2

x = 5/2 or x = -5/2

x in (-oo:-5/2) U (-5/2:5/2) U (5/2:+oo)

(2*x^2-(3*x)-5)/(25-(4*x^2)) = 0

(2*x^2-3*x-5)/(25-4*x^2) = 0

2*x^2-3*x-5 = 0

2*x^2-3*x-5 = 0

DELTA = (-3)^2-(-5*2*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)+3)/(2*2) or x = (3-49^(1/2))/(2*2)

x = 5/2 or x = -1

(x+1)*(x-5/2) = 0

((x+1)*(x-5/2))/(25-4*x^2) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-5/2 )

x-5/2 = 0 // + 5/2

x = 5/2

x in { 5/2}

x = -1

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